.1x^2-30x+2000=0

Solution for .1x^2-30x+2000=0 equation:

.1x^2-30x+2000=0

a = .1; b = -30; c = +2000;
Δ = b2-4ac
Δ = -302-4·.1·2000
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10}{2*.1}=\frac{20}{0.2}
=100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10}{2*.1}=\frac{40}{0.2}
=200
$